(y + z2) * x
(5 + 3(2)) * 2
(5 + 6) * 2
11 * 2
Your answer is 22
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
The slope of the line is -(1/2)
Answer:
When two atoms have shared electrons, it is not distinguishable from what atom they are because they are shared in the same orbit, it is called a covalent bond.
Step-by-step explanation:
Atoms in a covalent bond share one or more electrons in the last of their orbitals, the number of electrons in the last orbital will depend on the element in question.
