When added, these two angles are supplementary, meaning that their sum is 180. This means that we can do the following to find x, and eventually DBC:
3x+67+4x+50=180
Simplifies to:
7x+117=180
Then by the Subtraction Prop. of Equality:
7x=63
Then divide by 7 on both sides to get that x=9.
We then substitute 9 into angle DBC.
4(9)+50
=36+50
DBC=86
:)
Can you help me in my recent
Answer:
y = 3x^2-6x+3 one real solution
y = -x^2 - 4x + 7 two real solution
y = -2x^2+9x-11 two complex solutions
Step-by-step explanation:
b^2-4ac = 0 1 repeated real solution
b^2-4ac > 0 2 distinct real solutions
b^2-4ac < 0 2 complex solutions