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Umnica [9.8K]
3 years ago
5

120 is the product of — 12 and b

Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0
-10 is the correct answer
Elza [17]3 years ago
6 0
B= -10

Explanation: Divide 120 by -12 to receive the answer, -10. To check, do the opposite operation.
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Help with my homework:)
Bumek [7]

Answer:

Step-by-step explanation:

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3 0
3 years ago
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Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

d = -33-(-15)

d = -33+15

d = -18

Now, nth term  of an arithmetic sequence is

a_n=a+(n-1)d

Substitute a=-15 and d=-18.

a_n=-15+(n-1)(-18)

a_n=-15-18n+18

a_n=-18n+3

Therefore, the nth term of the given arithmetic sequence is a_n=-18n+3.

4 0
3 years ago
Determine whether the number is closest 0, or 1. explain your reasoning.
Vesnalui [34]
10/9 is 1 + 1/9 so it is closer to 1.
9/16 is 1/2 + 1/16 so it is a little over 1/2 which means it is closer to 1.
2/15 is way under a 1/2 so it is closer to 0.
7 0
3 years ago
What is the least common multiple you should use to find 4/5 + 5/6
amm1812

Answer:

30 is the lest common multiple

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
A confectioner bought 15 chocolates for Rs. 1. If he sold all chocolates at 25% profit, how many chocolates were sold for Rs. 1?
shutvik [7]

Answer:

He sold 12 chocolates for 1 Re.

Step-by-step explanation:

He bought 15 chocolates for 1 Rupee

He sold for a profit of 25%

Sale price = profit + cost price

SP= 25%of 1 + 1 Re

SP = 0.25*1+ 1

SP = 1.25 Rs

He sold 15 chocolates fro 1.25 Rs

Chocolates            Rupees

15                            1.25

x                                1

Applying cross product

x*1.25= 15*1

x= 15*1/1.25

x= 12

He sold 12 chocolates for 1 Re.

4 0
3 years ago
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