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Deffense [45]
3 years ago
8

What is the equation of the line that passes through the point (2,−4) and has a slope of 2?

Mathematics
1 answer:
vivado [14]3 years ago
3 0

Answer:

y = 2x - 8

Step-by-step explanation:

Since you have the slope of the line and point that the line passes through, you can use "point-slope form", hence the name.

Point-slope form is: y-y_1=m(x-x_1)

Substitute the slope (2) into m, and substitute the x-value of the point into x_1 and the the y-value of the point into y_1.

  • y-(-4)=2(x-(2))

Simplify this equation.

  • y+4=2(x-2)

Distribute 2 inside the parentheses.

  • y+4=2x-4

Subtract 4 from both sides.

  • y=2x-8 is the final answer.
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Answer:

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Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

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Two lines with slopes m1 and m2 are perpendicular if:

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The given line has a slope m1=5, thus the slope of our required line is:

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The equation of the line now can be expressed as:

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\displaystyle 2=-\frac{7}{5}+b

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Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

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