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zheka24 [161]
3 years ago
9

One reason to check a solution in the original equation is the

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer:Lost myself

Step-by-step explanation:

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. identify the binomial<br> a. x2<br> b. x2 - 4x 2<br> c. x2 - 4<br> d. 2x2 3x - 1 y
tino4ka555 [31]

Answer: x^2 - 4

Step-by-step explanation:

Since a Binomial is an algebraic expression of the sum or the difference of two terms.

Therefore, For a binomial an expression must contain exactly two terms.

In a) x^2 there is only one term therefore it is not the Binomial.

In a) x^2-4x^2 = -3x^2,  there is only one term therefore it is not the Binomial.

In a) x^2-4 there is exactly two terms therefore it is a Binomial.

In a) 2x^2+3x-1y there are three terms therefore it is not the Binomial.

6 0
3 years ago
Read 2 more answers
Party punch cost $2.50 per half gallon how much would 6 gallons cost
saveliy_v [14]

2.4 is the answer i think

7 0
4 years ago
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2. Sam has two part-time jobs, delivering pizza and mowing lawns. He makes $9/hr delivering pizza and $7/hr mowing lawns. Last w
frutty [35]

Answer:

<h2>22 hours and 10 hours </h2>

Step-by-step explanation:

let the jobs be x and y, so that

x+y=32--------1

9x+7y=248----2

x=32-y

substitute x=32-y for x in equation 2 we have

9(32-y)+7y=248

open bracket we have

288-9y+7y=248

-2y=248-288

-2y=-40

2y=40

divide both sides by 2 we have

y=40/2

y= 10 hours

subtitute y=10 for y in equation 1 to find x

x+10=32--------1

x=32-10

x=22

x=22 hours

4 0
3 years ago
How can you find the LCM of two rational expressions if the polynomials cannot be factored?
Leviafan [203]

Answer:

To find the LCD of two rational expressions, we factor the expressions and multiply all of the distinct factors. For instance, if the factored denominators were (x+3)(x+4) ( x + 3 ) ( x + 4 ) and (x+4)(x+5) ( x + 4 ) ( x + 5 ) , then the LCD would be (x+3)(x+4)(x+5) ( x + 3 ) ( x + 4 ) ( x + 5 ) .

7 0
2 years ago
Which of the following is equal to 5⁄7? <br> A. 45⁄63<br> B. 54⁄63<br> C. 35⁄63<br> D. 42⁄63
Iteru [2.4K]

\bf \cfrac{45}{63}\implies \cfrac{9\cdot 5}{9\cdot 7}\implies \cfrac{9}{9}\cdot \cfrac{5}{7}\implies 1\cdot \cfrac{5}{7}\implies \cfrac{5}{7}

7 0
3 years ago
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