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Tanzania [10]
3 years ago
11

The table shows the number of games a team won and lost last season. Wins and Losses Last Season Number of Games Wins 24 Losses

16 Greg has tickets to six of the team’s games this season. He is designing a simulation, using last year’s wins and losses, to predict whether the team will win or lose each of the games he attends. Which tool is most appropriate for use in a simulation that fits the data? a coin with one side representing a win and the other representing a loss a 6-section spinner with congruent sections, 4 representing a win and 2 representing a loss a 5-section spinner with congruent sections, 3 representing a win and 2 representing a loss an 8-sided die with 5 sides representing a win and 3 sides representing a loss
Mathematics
2 answers:
cestrela7 [59]3 years ago
7 0

Answer:

C?

Step-by-step explanation:

sergiy2304 [10]3 years ago
4 0

Answer:

The table shows the number of games a team won and lost last season is explained below in details.

Step-by-step explanation:

"Greg is creating a simulation, using previous year’s wins and losses, to foretell the team's conclusion.

He has six tickets for the team’s matches. The device which is most suitable for application in a simulation that implements the data is Probability.

Probability is the ratio of the probability that an incident will take place. The more eminent is the probability of an incident, there are likewise outcomes that the game will happen.

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Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa
inessss [21]

Answer:

a) 0.4164

Step-by-step explanation:

Mean lifespan (μ) = 18.8 days

Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

z=\frac{X- \mu}{\sigma} \\z=\frac{X- 18.8}{2}

For X=12.04 days:

z=\frac{12.04 - 18.8}{2} \\z=-3.38

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

z=\frac{18.38 - 18.8}{2} \\z=-0.21

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

P=41.68-0.036\\P=41.64\%\ or\ 0.4164

6 0
3 years ago
Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig
Nady [450]

Answer:

D = 45+19*sin(\frac{\pi}{12}*t)

Step-by-step explanation:

The amplitude (A) and the mean (M) temperature are given by:

A=\frac{64-26}{2}\\ A= 19\\M=\frac{64+26}{2}\\ M= 45\\

The mean temperature, 45 degrees. occurs at midnight (t=0) and the frequency is f=24h. Therefore, the temperature D, in degrees, as a function of t, in hours, is:

D = M+A*sin(\frac{2\pi}{24}*t)\\D = 45+19*sin(\frac{\pi}{12}*t)

5 0
4 years ago
In a Calculus class, there are 11 freshman and 15 sophomores; 5 of the sophomores are females,
KATRIN_1 [288]

Answer:

61.5%

Step-by-step explanation:

Let's find all the demographics first:

Sophomores in the class(total 15):

Female: 5

Male : 10

Freshmen in the class(total 11):

Female: 3

Male: 8

There are 11 freshmen(male and female) and 5 female sophomores. Thus, the probability of choosing one of these 16 people in a class of 26 is 16/26 or 61.5%.

4 0
3 years ago
Use decimals to give the ordered pair for point U. Remember to putyour odered pairs in parenthesis.
Gnoma [55]

Answer:

(0,2.5)

Step-by-step explanation:

3 0
3 years ago
WILL GIVE BRAINLIEST!!!
tamaranim1 [39]

Answer:

The correct answer is D

Step-by-step explanation:

6 0
3 years ago
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