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cricket20 [7]
3 years ago
7

Your checking account balance is $50. You spend $11 and then deposit $27.

Mathematics
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

$66

Step-by-step explanation:

$50- $11= $39

$39+ $27= $66

alexgriva [62]3 years ago
5 0

Answer:

66$

Step-by-step explanation:

50$-11$+27$

66$

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torisob [31]

so obviously first of all find three sherical objects or balls of varioius sizes to make it easier get a large medium and small sized.

then on scratch paper sketch those objects (im assuming by the looks of it you would trace them if not just draw them then take measuring tape or a ruler across to measure said object) now you arent told what units to measure in but id assume to stick with one unit either inches or cm

mesure the length across which is the circumference

now you would just have to do your calculations by finding the radius and volume and surface area

remember volume is (*units) cubed and suface area is (*units) sqared

6 0
3 years ago
The product of (-5xy2) and (-4x2y)
solong [7]

Combine like variables:

(20x^2)(2y^3)

Combine coefficients:

40(x^2)(y^3)

3 0
3 years ago
Fake Question: Should Ujalakhan01 be a moderator? (If you could answer I'd appreciate it haha.)
Dovator [93]

Answer:

a^9 + b^ 5 + c^{13}

Step-by-step explanation:

(a^5 \times a^4)+(b^2 \times b^3) + (c^7 \times c^6)

When bases are same and it is multiplication, then add the exponents.

(a^{5+4})+(b^{2+3})+(c^{7+6})

(a^9)+(b^ 5) + (c^{13})

Apply rule : (a^b)=a^b

a^9 + b^ 5 + c^{13}

8 0
3 years ago
Read 2 more answers
Please help!
777dan777 [17]

Answer:

\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}

Step-by-step explanation:

Use formulas for the volumes:

V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.

1. When r=1,

V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.

2. When r=2,

V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.

3. When r=3,

V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.

4. When r=4,

V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.

5. When r=5,

V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.

Note that for all r,

\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.

8 0
4 years ago
Read 2 more answers
Can someone please help me
gulaghasi [49]

Answer:

544 units^2

Step-by-step explanation:

Please see attached picture for full solution.

8 0
3 years ago
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