Answer:
50 ft2
Step-by-step explanation:
im not sure if this is right but this is what i got when i worked it out
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Total tickets: 7
Popcorn costs: $5
total cost: $54
7x + 5 = 54
- 5 -5
7x = 49
49/7 = 7
Final Answer: x=7
since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side
now, let us use the pythagorean theorem, to find the opposite side, or "b"
so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means, -15 = b
so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then
626. tangent because adjacent and hypotenuse are given. tan= o/a
tan(9)= .1584
o/.1584 = 3954/1
cross multiply.
o= .1584 * 3954
o= 626
