Answer:
Below
Step-by-step explanation:
Substituting the given values:
f(6) = 6(2/3) - 2 = cube root of 6^2 - 2 = cube root 36 - 2
f(-6)= (-6)(2/3) - 2 = cube root of(-6)^2 - 2 = cube root 36 - 2
So This is true,
f(6) = cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019
2 * f(3) = 2 * (cube root of 3^2 - 2 ) = 2 * (cube root of 9 - 2) = 0.1602
So False,
Answer: Answer is in the steps..
Step-by-step explanation:
f(x)=
- 3x -5
A) To find the x intercepts of a parabola we have to set the whole equation equal zero because the x intercept is when y equal zero in other words where f(x) equal zero.
- 3x - 5 = 0 Now solve using quadratic formula.
x = -b±
x = 3 ±
x = 3 ±
/ 2a
x= 3 ± 7 /4
x= -1 or x = 5/2
The x intercepts are (5/2,0) and (-1,0)
B) The graph vertex of the graph of f(x) is going to be at a minimum because the leading coefficient of the function has a positive integer which means the parabola will open up and its vertex will be at the minimum point.
Using the x coordinates we could find their average and find the x coordinate of the vertex.
=
= 3/4
The x coordinate of the vertex is 3/4 so we will input that into the equation and solve for the y coordinate
= 18/16 - 9/4 -5 = -49/8
The y coordinate of the vertex is -49/8
So the vertex is (3/4, -49/8)
C) First I will graph the vertex and then graph he two x intercepts and connect then like a U shape.
Answer:
Step-by-step explanation:
1). Equation of a line which has slope 'm' and y-intercept as 'b' is,
y = mx + b
If slope 'm' = 1 and y-intercept 'b' = -3
Equation of the line will be,
y = x - 3
x - y = 3
2). Equation of a line having slope 'm' and passing through a point (x', y') is,
y - y' = m(x - x')
If the slope 'm' = 1 and point is (-1, 2),
The the equation of the line will be,
y - 2 = 1(x + 1)
y = x + 1 + 2
y = x + 3
x - y = -3
3). Equation of a line passing through two points
and
will be,

If this line passes through (-2, 3) and (-3, 4),

y - 3 = -1(x + 2)
y = -x - 2 + 3
y = -x + 1
x + y = 1
Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
Answer:
C. 114
Step-by-step explanation:
bikes have 2 wheels
skateboards have 4 wheels
incline skates have 8 wheels in total
7*2 = 14
9*4 = 36
8*8 = 64
if you add all of these up you get 114 wheels in total. 8*8 was from 24-7-9 = 8