Ivan only, because an odd number of negatives does not always make negatives while an even number does.
EQ. 1: x + y = 8
EQ. 2: 4x-y = 7
Rewrite EQ. 1 as EQ. 3: x = 8-y
Replace x in EQ.2 with EQ. 3:
4(8-y) - y = 7
Use the distributive property:
32 - 4y - y = 7
Combine like terms:
32 - 5y = 7
Subtract 32 from each side:
-5y = -25
Divide both sides by -5
y = -25 / -5
y = 5
Now replace y with 5 in EQ. 3 to solve for X:
x = 8-5
x = 3
The point of intersection is X = 3, Y = 5, which is written as (3,5)
Answer:
3.70
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
Shape: Rectangle
Diagonals: AC and BD

Required
Determine BD
From the question, we understand that the shape is a rectangle and its diagonals are AC and BD
Every rectangle has 2 diagonals, both of which are equal.
This implies that:

Recall that:

Hence,

Answer:
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