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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
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V and Y, W and X: The second option. If you look at your congruency markings the one with the one mark will match with the one with one mark. The one with two marks will match with the one with two marks. The one with three marks corresponds to the one with three marks.
7^(1/3) : 7^( 1/5)= 7^(1/3 -1/5)=7^[(5-3)/15]= 7^[2/15]
the answer is D
