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ZanzabumX [31]
3 years ago
11

) Which value is the solution of the equation 54 = 6n? ​

Mathematics
1 answer:
xeze [42]3 years ago
8 0

54 = 6n     divide 6 on both sides, 6's will cancel on the right.

__    __     solve for 54 ÷ 6 = 9

6      6

n = 9, choice 4 -- <em>final answer</em>

hope this helps :)

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Step-by-step explanation:

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Solve the following equation 3+3x+9(9x)
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Write the function , √(x^3+6)/√(x^3-9) as a composition of three or more non-identity functions.
tamaranim1 [39]

Answer:

h \circ m \circ n \text{ where } h(x)=\sqrt{x} \text{ and } m(x)=1+\frac{15}{n} \text{ and } n(x)=x^3-9

Step-by-step explanation:

Ok so I see a square root is on the whole thing.

I'm going to let the very outside function by h(x)=sqrt(x).

Now I'm can't just let the inside function by one function g(x)=\frac{x^3+6}{x^3-9} because we need three functions.

So I'm going to play with g(x)=\frac{x^3+6}{x^3-9} a little to simplify it.

You could do long division. I'm just going to rewrite the top as

x^3+6=x^3-9+15.

g(x)=\frac{x^3-9+15}{x^3-9}=1+\frac{15}{x^3-9}.

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Now my last function will be n(x)=x^3-9.

So my order is h(m(n(x))).

Let's check it:

h(m(x^3-9))

h(1+\frac{15}{x^3-9})

h(\frac{x^3-9+15}{x^3-9})

h(\frac{x^3+6}{x^3-9})

\sqrt{ \frac{x^3+6}{x^3-9}}

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3 years ago
What is the answer to my question
Vedmedyk [2.9K]
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Step-by-step explanation:
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3 years ago
In the given right triangle, write all trigonometric ratios ?
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Answer:

see below

Step-by-step explanation:

You will need the hypotenuse   12 ^2 + 9^2 = h^2   h = 15

In a right triangle:

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sin s  =   S A H  = Opposite / Hypotenuse =   12/15

cos r = C A H  = Adjacent / Hypotenuse    = 12/ 15

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Tan r = 9/12

arc cos(theta) = theta = arccos(9/15) = 53.13 degrees

4 0
2 years ago
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