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2 years ago

Someone please help! im kinda in a rush

Mathematics

1 answer:

ASHA 777 [7]2 years ago

5 0

Answer:

0.8 and 0.9

Step-by-step explanation:

rounded to the tenths, its 0.7

so 0.8 and 0.9 are the smallest and largest number

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Mr. Moss had 2 gallons of paint. He painted 3 doors. How many benches can he paint with the paint that is left? Show your work.

RUDIKE [14]

Answer:

uh depends on how much paint he used for the doors and how much paint he needs for the benches

Step-by-step explanation:

8 0

2 years ago

What is the distance between the points located at 7 and -1 1/2 on the number line?

Temka [501]

Answer:

8 1/2

Step-by-step explanation:

They are on opiate sids of zero so add the absolute values together to get 1/2

7 0

3 years ago

you randomly draw a marble from a bag of marbles that contains 7 bless marbles, 2 green marbles,and 1 red marble. What is the th

podryga [215]

Answer:

2:10

Step-by-step explanation:

So add up all the marbles that are in the bag, Then they're asking you of not you getting the green marble and there's 2 green marbles. So it would be the ratio 2:10. Brainliest me please.

5 0

2 years ago

Help me on this please

zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each IMAGE you should perform the following steps:

List the vertex points of the preimage (the original figure) as ordered pairs.

Apply the transformation rule to every point of the preimage

List the image of each vertex after applying each transformation, also as ordered pairs.

1. (x, y) → (x + 3, y - 2)

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage Vertices of the image

a) (-5,2) (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5) (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4) (-1 + 3, 4 - 2) = (2, 2)

2. (x,y) → (x - 3, y + 5)

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage Vertices of the image

a) (0, -3) (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3) (3 - 3, -3 + 5) = (0, 2)

c) (3, -1) (3 - 3, -1 + 5) = (0, 4)

d) (5, -1) (5 - 3, -1 + 5) = (2, 4)

3. (x, y) → (x + 4, y)

The rule represents a translation 4 units to the right.

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 4, -2) = (-1, -2)

b) (-3, -5) (-3 + 4, -2) = (1, -2)

c) (-1, -2) (-1 + 4, -2) = (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3) (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3) (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5) (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2) (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4) (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4) (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5) (-2 + 3, -5 + 1) = (1, -4)

5. (x, y) → (x, y - 4)

This is a translation four units down

Vertices of the preimage Vertices of the image

a) (0, 2) (0, 2 - 4) = (0, -2)

b) (0,1) (0, 1 - 4) = (0, -3)

c) (2, 2) (2, 2 - 4) = (2, -2)

d) (2,0) (2, 0 - 4) = (2, -4)

6. (x, y) → (x - 1, y + 4)

This is a translation one unit to the left and four units up.

Vertices of the pre-image Vertices of the image

a) (-4, -1) (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5) (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4) (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5) (-2 - 1, -5 + 4) = (-3, -1)

8 0

2 years ago

Use the law of sines to find the value of w.

Lunna [17]

Option B: 4.0 cm is the value of w

Explanation:

It is given that $\angle W= 39$ , $\angle U=31$ , $VW=3.3$ and $UV=w$

Using the law of sines, we have,

$\frac{sin U}{3.3} =\frac{sin W}{w}$

Substituting the values, we have,

$\frac{\sin 31}{3.3}=\frac{\sin 39}{w}$

Cross multiplying, we get,

$(sin31) w=3.3( \sin 39)$

Simplifying, we have,

$0.515w=2.077$

Dividing both sides by 0.515, we have,

$w=4.0$

Thus, the value of w is 4.0 cm

Hence, Option B is the correct answer.

4 0

2 years ago

Read 2 more answers