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makkiz [27]
3 years ago
7

Could someone please help me with these

Mathematics
1 answer:
eimsori [14]3 years ago
4 0
4. Normal body temperature is 98.6 degrees Fahrenheit, although it varies slightly for some people. Someone ?
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Basic car costing 26,500 with options costing 725.00. There is a 6% sales tax in the state and a combined 50.00 license and regi
GaryK [48]

26500 + 725 = 27225

27225 x 0.06 = 1633.5

27225 + 1633.50 = 28858.50 + 50 = 28908.50 total cost

5 0
3 years ago
Identify the expression which represents the calculation “subtract 3 from 15, then divided by 6
matrenka [14]

Answer:

\frac{15-3}{6}

Step-by-step explanation:

You would start by writing the expression for “subtract 3 from 15", which would be \frac{15-3}{6}, then you would add on "then divided by 6", which would make it

4 0
2 years ago
Read 2 more answers
Rewrite the equation to isolate the variable.. df= g- 10 for d
ehidna [41]
Df = g - 10

To solve for d, divide both sides by f.

df / f = (g - 10) / f

d = (g - 10) / f

I hope this explains it.
6 0
3 years ago
What is the value <br> 6=a/4+2
Tpy6a [65]

Answer:

a=16

Step-by-step explanation:

16/4+2 = 6

Thus the answer is 16

7 0
3 years ago
Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part
katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

8 0
3 years ago
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