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4 years ago

- Do two points always, sometimes, or never determine a line? Explain

Mathematics

1 answer:

White raven [17]4 years ago

8 0

Answer:

Always

Step-by-step explanation:

if two points lie in a plane, then the entire line containing those points lies in that plane

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Please help asap 20 pts + brainliest to right/best answer

AleksAgata [21]

Answer:

(-1,-2)

Step-by-step explanation:

The vertex of the parabola is the minimum or maximum point of the parabola. It is located along the line of symmetry.

Looking at the graph, the minimum point is (-1,-2)

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4 years ago

If Line EF is equal to x + 9, Line FG is equal to 14 + x, Line GH is equal to x + 3, Line FH is equal to 12 and if Line EH is eq

ololo11 [35]

The answer is 24= EG

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3 years ago

PLEASE HELP!!! Which choice is a solution to the system of equations below?

frozen [14]

Answer:

Step-by-step explanation:

4y = 12x + 16

3x = y - 4

y = 3x + 4

using that in the first equation

4(3x+4) = 12x + 16

12x + 16 = 12x + 16

=> both lines/equations are identical, so they have infinitely many solutions.

7 0

3 years ago

Can someone please help me!?

Lelechka [254]

Your answer would be 8, i recommend a website called desmos for graphing online

8 0

3 years ago

Question 3 (4 marks)

Jet001 [13]

Answer:

3.1 0.6912 = 69.12% probability that one or two out of the next four customers will make a purchase.

3.2 0.9744 = 97.44% probability that at least one out of the next four customers do not make a purchase

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they make a purchase, or they do not. The probability of a customer making a purchase is independent of any other customer. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

40% of all customers walking into their store will buy at least one item on that occasion.

This means that $p = 0.4$

4 customers:

This means that $n = 4$

3.1 What is the probability that one or two out of the next four customers will make a purchase?

This is:

$P(1 \leq X \leq 2) = P(X = 1) + P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{4,1}.(0.4)^{1}.(0.6)^{3} = 0.3456$

$P(X = 2) = C_{4,2}.(0.4)^{2}.(0.6)^{2} = 0.3456$

$P(1 \leq X \leq 2) = P(X = 1) + P(X = 2) = 0.3456 + 0.3456 = 0.6912$

0.6912 = 69.12% probability that one or two out of the next four customers will make a purchase.

3.2. What is the probability that at least one out of the next four customers do not make a purchase?

This is:

$P(X \leq 4) = 1 - P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.4)^{4}.(0.6)^{0} = 0.0256$

$P(X \leq 4) = 1 - P(X = 4) = 1 - 0.0256 = 0.9744$

0.9744 = 97.44% probability that at least one out of the next four customers do not make a purchase

3 0

3 years ago