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Agata [3.3K]
3 years ago
6

Solve the system of equations 3x – 3y = 30 and 2x + y = 11 by combining the equations.

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0
Times bottom equation by 3 and top by 2 to get the same coefficient of x
6x-6y=60
6x+3y=33
Minus the bottom by the top
-9y=27
y=-3
substitute this in to one of the equations
2x -3 = 11
add 3 to both sides
2x=14
x=7
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babunello [35]

Answer: I do not understand the options you gave but but cos30º is equal to \sqrt{3}/2 which is 0.86602540378.

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3 years ago
Which equation is equivalent to log (x+5) = 27
Tresset [83]

Answer:

(22+5)=27 or  (x+y)=27

Step-by-step explanation:

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1. Bob is looking to buy a new baseball cap with his favorite team’s logo on it. He finds one that normally sells for $32. If a
GenaCL600 [577]

Answer:

The total cost is $34.24.

Step-by-step explanation:

Given : Bob is looking to buy a new baseball cap with his favorite team’s logo on it. He finds one that normally sells for $32. If a 7% sales tax is added.

To find : What is the total cost?

Solution :

The sales price = $32

The tax rate = 7%=0.07

The sales tax is given by,

\text{Sales tax}=\text{Rate}\times \text{Price}

\text{Sales tax}=0.07\times 32

\text{Sales tax}=2.24

Now, adding to sales price

Total cost = 32+2.24

Total cost = $34.24

Therefore, the total cost is $34.24.

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3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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BabaBlast [244]

Answer:

A

Step-by-step explanation:

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