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lora16 [44]
3 years ago
13

Using the FOIL method, find the product of x - 2 and x - 3 .

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
FOIL = first, outside, inside, last
(x - 2)(x - 3)
x^2 -3x - 2x + 6
x^2 - 5x + 6
Ray Of Light [21]3 years ago
3 0

Answer:

<h3>\boxed{ {x}^{2}  - 5x + 6}</h3>

Step-by-step explanation:

\mathsf{(x - 2)(x - 3)}

Multiply each term in the first parentheses by each term in the second parentheses ( FOIL )

\mathsf{x×x - 3x - 2x - 2 × ( - 3 )}

Calculate the product

\mathsf{ {x}^{2}  - 3x - 2x - 2 \times  (- 3)}

Multiply the numbers

\mathsf{ {x}^{2} - 3x - 2x  + 6 }

Collect like terms

\mathsf{ {x}^{2}  - 5x + 6}

Hope I helped!

Best regards!

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Find the gradient of the line Joining the points p(-2,6) and Q(3,-2)​
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Answer:

-  \frac{8}{5}

Step-by-step explanation:

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

(x₁, y₁) is the 1st coordinate while (x₂, y₂) is the 2nd coordinate.

Gradient of the line

=  \frac{6 - ( - 2)}{ - 2 - 3}

=  \frac{6 + 2}{ - 5}

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Mashcka [7]

we know that

A difference of squares problem can be factored as follows:

a^{2}-b^{2} =(a+b)(a-b)

in this problem we have

t^{4}-16

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the term

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substitute

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I NEED HELP ASAP(look at the picture for the problem)
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Answer:

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Step-by-step explanation:

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