Question

A gas at 127 celsius and 10.0 L expands to 20.0 L. What is the new

Answer 1

Answer:

T₂ = 800 K

Explanation:

Given that,

Initial temperature of the gas, T₁ = 127°C = 400 K

Initial volume, V₁ = 10 L

Final volume, V₂ = 20 L

We need to find the new temperature.

The volume of a gas is directly proportional to its Kelvin temperature.

Let T₂ is the new temperature. So,

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{20\times 400}{10}\\\\T_2=800\ K$

So, the new temperature of the gas is 800 K.