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Nikolay [14]
3 years ago
11

Find the missing side of each triangle

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0
<h2 /><h3><u>Given :</u></h3>

• Hypotenuse (H) = 15 in

• Base (B) = 12 in

<h3><u>To calculate :</u></h3>

• Perpendicular (P) [x]

<h3><u>Calculation :</u></h3>

By using pythagoras property,

\longmapsto \sf { H^2 =B^2 + P^2 }

\longmapsto \sf { (15)^2 =(12)^2 +(x)^2 }

\longmapsto \sf { x^2 = (15)^2 - (12)^2 }

\longmapsto \sf { x^2 = 225 - 144 }

\longmapsto \sf { x^2 = 81 }

\longmapsto \sf { x = \sqrt{81} }

\longmapsto \sf \red { x = 9 \: in}

So, the value of<u> x (perpendicular) is 9 </u><u>in</u>.

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seraphim [82]

Answer:

\boxed{\bold{2y^2-4y-24}}

Step By Step Explanation:

Expand \bold{3\left(2y-8\right): \ 6y-24}

\bold{6y-24-2y\left(5-y\right)}

Expand \bold{-2y\left(5-y\right): \ -10y+2y^2}

\bold{6y-24-10y+2y^2}

Simplify \bold{6y-24-10y+2y^2}

\bold{2y^2-4y-24}

7 0
3 years ago
Which inequality represents the number line below?
makvit [3.9K]

Answer

try the inequality x >3

Step-by-step explanation:

because the circle is open and the line would have started at the 5 so the line would be going >  and the circle ends at the 3

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3 0
3 years ago
A flagpole that was originally 24 feet tall has cracked 9 feet from the ground and has fallen as if hinged. Find
Dimas [21]
The top of the flag pole touched the ground 12 feet from the base.

Since it cracked 9 feet from the base, 9 is the vertical leg of the right triangle formed.  The rest of the flagpole, 24-9=15, is the hypotenuse, as it is slanted down to the ground.  The missing side is the horizontal leg, which we will call b:

9²+b²=15²
81+b²=225

Subtract 81 from both sides:
81+b²-81=225-81
b²=144

Take the square root of both sides:
√b²=√144
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8 0
4 years ago
You want to buy a house that is worth $200,000. You finance the house for 30 years at 4.2%. How much interest do you pay over th
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4 years ago
The weight distribution of parcels sent in a certain manner is normal with mean value 15 lb and standard deviation 3.3 lb. The p
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Answer: 23.7 lb

Step-by-step explanation:

Mean m = 15 lb

Standard deviation d = 3.3 lb

To determine the surcharge weight, we need to know the highest weight of 99% of the parcels.

P(z<x) = 0.99 = ¢(Z)

Z = 2.33

Since Z = (x - m)/d

x = dZ + m

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x = 22.7 lb

Therefore, the highest weight for 99% if the parcels is 22.7 lb.

That is, the surcharge weight = 22.7 + 1 = 23.7 lb

3 0
3 years ago
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