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3 years ago

Which three side lengths best describe the triangle in the diagram?

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

Answer:

d. 6cm, 6cm, 6cm

Step-by-step explanation:

each one of the rulers is lined correctly and shows that it is 6 cm

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On the graph, two right triangles have the line as the hypotenuse. In this task, you will use these triangles to show that the s

Sav [38]

Answer:

i need the anwser to

Step-by-step explanation:

6 0

3 years ago

An equal number of juniors and seniors are trying out for six spots in this year's decathlon

il63 [147K]

There are 50 different possible debating teams that could be selected as obtained using COMBINATION.

Since there are EQUAL number of juniors and seniors ;

Then we have 5 of each.

Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION

since the team MUST contain 4 SENIORS and 2 JUNIORS

4 Seniors from 5 = 5C4 = 5

2 Juniors from 5 = 5C2 = 10

Hence, (5C4 * 5C2) = 5 * 10 = 50

Hence, there are 50 different possible debating teams that could be selected.

Learn more :

brainly.com/question/8018593

7 0

3 years ago

Plz help what does this mean

kotykmax [81]

The Correct Answer is C)3 Just divide 6/2 Then you end up with 3

8 0

3 years ago

Suppose there are n rectangular prisms stacked on top of each other in various ways to form one solid. Each has l = w and a heig

horsena [70]

The volume of the resulting solid will be the volume of one rectangular prism times n.
The the volume of a rectangular prism is V=lwh. But since l=w (cross-section is a square), we now have V=l²h.

The volume of the resulting solid will be V = nl²h or V = nw²h.

6 0

4 years ago

Situation: a 25 gram sample of a substance that’s used for drug research has a K-value of 0.1205

Lelu [443]

The decay model is given as

$N=N_0e^{-Kt}$

The substance's half-life is the time it takes for the substance to decay to half its original amount. In other words, it's the time $t$ such that $N=\dfrac{N_0}2$ . Substituting into the model, you have

$\dfrac12=e^{-Kt}$

You can solve for $t$ now.

$\dfrac12=e^{-Kt}$
$\implies\ln\dfrac12=\ln e^{-Kt}$
$\implies-\ln2=-Kt\ln e$
$\implies\dfrac{\ln2}K=t\approx5.7523\text{ days}$

8 0

3 years ago