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Serga [27]
3 years ago
12

The trinomial x^2+bx-c has factors of (x+m)(x-n), where m,n, and b are positive. What is the relationship between the values of

m and n?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
10 0
In the given above, we have an equation that is equal to, 

    x² + bx - c = (x + m)(x - n)

If we are to apply distributive property on the items at the right hand side of the equation, the equation becomes,
     x² + bx - c = x² - nx + mx - mn

Simplifying,
    x² + bx - c = x² + (m-n)x - mn

If b is a positive number, m-n should be positive. Therefore, the value of m should be greater than the value of n in order for m-n to become positive. 
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If f(x)=3[x-2],what is f(5.9)?<br> 9 <br> 10<br> 11<br> 12
inna [77]
<span>f(x)=3[x-2]
So, f(5.9) = ?
f(5.9) = 3(5.9 - 2)
=3(3.9)
=11.7 = 12
Thus, the answer is 12.

</span>
8 0
3 years ago
Read 2 more answers
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GaryK [48]
Jayden ran 1/5 of his total distance in 1 minute. His total distance is 6/5 of a kilometer. He ran 6/25 of a kilometer in 1 minute or 3/5 of a lap.
7 0
3 years ago
Gavin rented a truck for 5 days. The truck
NeX [460]
$55x5 days= $275
$285.20-275=$10.20
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Answer= 68 miles
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3 years ago
If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the b
strojnjashka [21]
Surface area of box=1200 cm² 
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
 = the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>


<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>

by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>


<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000 
v=4000</span>
4 0
3 years ago
For every quarter he spends, Reggie receives 50 food pebbles to feed the fish. Reggie has thrown 350 food pebbles into the fish
deff fn [24]

Answer:

7 quarters are spent for throwing 350 food pebbles in pond.

Step-by-step explanation:

Given:

Reggie receives 50 food pebbles for every quarter he spends.

Number of food pebbles he has = 350

Let the number of quarters spent for 350 pebbles be 'x'.

Now, using proportion and cross multiplication method, we can find 'x'.

<u><em>1 quarter is equivalent to 50 pebbles thrown in pond.</em></u>

<u><em>So, 'x' quarters is equivalent to 350 pebbles thrown in pond.</em></u>

\frac{1}{50}=\frac{x}{350}\\\\Cross\ multiplying\\\\50x=350\\\\x=\frac{350}{50}\\\\x=7

So, 7 quarters are spent for throwing 350 food pebbles in pond.

6 0
3 years ago
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