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Whitepunk [10]
3 years ago
8

a bag contains colored gumdrops 5 are cherry 3 are strawberry 2 are grape. a gumdrop will be randomly selected from the bag what

is the probability in decimal form that the gumball selected will be grape​
Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

probablity of grapes = 0.2

Step-by-step explanation:

here's the solution : -

probablity of grapes =

\frac{number \: of \: grapes}{total \: fruits}

=》

\frac{2}{2 + 3 + 5}

=》

\frac{2}{10}

=》

0.2

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11. What is the location of the vertex of the parabola defined by f(x) = −3x2 − 18x − 35 and in what direction does the parabola
lbvjy [14]

11. The given parabola has equation: f(x)=-3x^2-18x-35

We complete the square to have the function in the vertex form: f(x)=-3(x^2+6x)-35

f(x)=-3(x^2+6x+9)+3*9-35

f(x)=-3(x^2+6x+9)+27-35

f(x)=-3(x+3)^2-8

The vertex is (-3,-8), the graph opens down because a=-3<0

Ans: B. Vertex: (−3, −8), opens downward

12.  We know the graph of y=x^2  is a parabola that opens up and has its minimum point at the origin.

The range of this function is y\ge 0

A straight line that has its y-intercept below the x-axis (y=3x-6) will not intersect y=x^2 and hence will form a system with no solution.

Ans: D. y equals x squared, y equals 3x minus 6

 14.  We want to find the zeros of x^2+21x=5x-63

x^2+21x-5x+63=0

x^2+16x+63=0

The factored form is (x+7)(x+9)=0

x=-7\:or\: x=-9

Ans: C. x = −7, −9

15. The given quadratic expression is 6x^2-17x+10

We split the middle term to obtain:

6x^2-12x-5x+10=0

We factor by grouping to get:

6x(x-2)-5(x-2)=0

(x-2)(6x-5)=0

Ans: D. 6x − 5

8 0
3 years ago
Read 2 more answers
Sara threw her math book off a building . The height of the book, seconds after being thrownis modeled by the equation below. Th
Vikentia [17]

Answer: 70 ft

Step-by-step explanation:

Given

height of book is measured by the function is

h(x)=-5(x+2)(x-7)

when the book is thrown x=0

\therefore h(x=0)=-5(0+2)(0-7)\\\Rightarrow h(x=0)=70\ ft

The height of the book is 70\ ft

4 0
2 years ago
2. What is 9 squared. <br> a. 3<br> b. 81<br> C. 18<br> O d. 11
vitfil [10]

Answer:

81

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Can someone check whether its correct or no? this is supposed to be the steps in integration by parts​
Gwar [14]

Answer:

\displaystyle - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}

Step-by-step explanation:

\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}

Given integral:

\displaystyle -\int \dfrac{\sin(2x)}{e^{2x}}\:\text{d}x

\textsf{Rewrite }\dfrac{1}{e^{2x}} \textsf{ as }e^{-2x} \textsf{ and bring the negative inside the integral}:

\implies \displaystyle \int -e^{-2x}\sin(2x)\:\text{d}x

Using <u>integration by parts</u>:

\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)

\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}

Therefore:

\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}

\displaystyle \textsf{For }\:-\int e^{-2x} \cos (2x)\:\text{d}x \quad \textsf{integrate by parts}:

\textsf{Let }\:u=\cos(2x) \implies \dfrac{\text{d}u}{\text{d}x}=-2 \sin(2x)

\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}

\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}

Therefore:

\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x

\textsf{Subtract }\: \displaystyle \int e^{-2x}\sin(2x)\:\text{d}x \quad \textsf{from both sides and add the constant C}:

\implies \displaystyle -2\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+\text{C}

Divide both sides by 2:

\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{4}e^{-2x}\sin (2x) +\dfrac{1}{4}e^{-2x}\cos(2x)+\text{C}

Rewrite in the same format as the given integral:

\displaystyle \implies - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}

5 0
2 years ago
On a map, 1 centimeter represents a distance of 15 kilometers. How many kilometers are represented by 7 centimeters?
marishachu [46]

Answer:

105

Step-by-step explanation:

15 times 7 =105

5 0
2 years ago
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