Answer:
The minimum number of different tanks needed to safely house all the fish is:
Step-by-step explanation:
To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:
- Tank 1: <em>A</em>
- Tank 2: <em>F</em>
- Tank 3: <em>G</em>
Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:
- Tank 1: <em>A, B, D</em>.
- Tank 2: <em>F, E, H</em>.
- Tank 3: <em>G, C</em>.
And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.
The answer is A. product.
Answer:
2 5/12 cups
Step-by-step explanation:
Map pours 3 2/3 cup of orange juice into measuring cup from a large container then he poured 1 1/4 cups back into the container
The amount of juice remaining in the measuring cup is calculated as:
3 2/3 - 1 1/4
= 3 - 1 + ( 2/3 - 1/4)
LCD = Lowest Common Denominator is 12
= 2 + (4 × 2 - 3 × 1/12)
= 2 + (8 - 3/12)
= 2 + 5/12
= 2 5/12 cups
Hence, the amount of juice remaining in the measuring cup = 2 5/12 cups of juice
The equation of this line in slope intercept form is y= 3/7x
