3 years ago

How do I write the sum of 24+40 as a product of the greatest common factor and another sum

Mathematics

1 answer:

9966 [12]3 years ago

7 0

Answer is 64 and a factor is 6/4 .

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I am not sure how sigma notation works, can somebody explain how to solve this? It isn't the second choice.

Masja [62]

Answer:

first answer is correct

Step-by-step explanation:

Hello, we want to write 2 + 4 + 6 + ... + 20

for n = 1, 2n = 2*1 =2

for n = 2, 2n = 2*2=4

for n = 3, 2n=2*3=6

etc

$\displaystyle \sum_{n=1}^{10} {2n} = 2*1 + 2*2 +2*3+2*4+...+2*10=2+4+6+8+...+20$

thanks

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2 years ago

8 x 1 5/12 = ????<br><br> Fraction

UNO [17]

For the answer is 10

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2 years ago

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Luis took out a 3 year loan for $4500 at a furniture store to be paid back

SVETLANKA909090 [29]

Answer:

$1252.13

Step-by-step explanation:

15.9% = .159

$4500 multiplied by .159 = $715.50

3 yrs = 36 months

36 months - 15 months = 21 months

21 months = 1.75 yrs.

$715.50 multiplied by 1.75 = $1252.13

7 0

3 years ago

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Econ Question, Please use the picture below to answer. The highlighted one is my guess (might be right or wrong I don't know).

mafiozo [28]

Answer:

Step-by-step explanation:

3 0

3 years ago

Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69

Elena L [17]

If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}$

3 0

2 years ago