You would set this up as Part÷Whole=Percent÷100
Part=117
Whole= X
Percent=78
117÷X=78÷100
Set these up as fractions and cross multiply. You will get 117×100=78X
117×100=11,700
Divide both sides by 78 and you get x=150
There were 150 problems
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Put a small dot on positive 4 and go down to -3 and out a big dot there and that’s your first coordinate
Answer:
The expression is 20 - 50/5
Step-by-step explanation:
First we have the quotient of 50 and 5.
This is written as:
50/5
And we know that this is equal to 10, but let's leave it as 50/5 for now.
Now we subtract this FROM 20, then we have the number 20, and we subtract 50/5 from it, this is written as:
20 - 50/5
Now we can also solve this:
20 - 50/5 = 20 - 10 = 10
Answer: 24 and 76
Step-by-step explanation:
{
d
+
q
=
100
10
d
+
25
q
=
2140
From the first equation, we have
d
=
100
−
q
Substituting that into the second equation, we have
10
(
100
−
q
)
+
25
q
=
2140
⇒
1000
−
10
q
+
25
q
=
2140
⇒
15
q
=
1140
⇒
q
=
1140
15
=
76
Knowing that
q
=
76
we can substitute that value into the first equation to obtain
d
+
76
=
100
∴
d
=
24
Thus, Sue has
24
dimes and
76
quarters.
