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maria [59]
3 years ago
8

The length of one side of a square pond is 15 feet. The pond is surrounded by a 3 foot wide walkway. What is the total area of t

he pond and the walkway, in square feet
Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

Area = 324 ft²

Step-by-step explanation:

Given

Length = 15ft

Walkway = 3ft

Required

Determine the area of the pond + the walkway

To calculate the required area, we need to get the total length of a side .

This is calculated by adding the length of a side of the pond and the side of the walkway

Total Length = Pond Length + Walkway

Total Length = 15ft + 3ft

Total Length = 18ft

Now, the required area can be calculated as thus:

Area = Total Length * Total Length

Area = 18ft * 18ft

Area = 324 ft²

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4 0
4 years ago
The radius of a sphere is multiplied by . What effect does this have on the volume of the sphere? A. The volume of the sphere is
Greeley [361]

Answer:

Option A. The volume of the sphere is multiplied by 1/343.

Step-by-step explanation:

The volume of a sphere can be obtained by the following formula:

V = 4/3πr^3

Let the initial volume (V1) of the sphere be:

V1 = 4/3πr^3 = (4πr^3)/3

Now, if we multiply the radius by 1/7, then the new volume (V2) of the sphere will be:

V2 = 4/3 x π x (1/7r)^3

V2 = 4/3 x π x 1/343r^3

V2 = (4πr^3)/1029

Now we determine the ratio of V2 : V1 as shown below:

V2/V1 = (4πr^3)/1029 ÷ (4πr^3)/3

V2/V1 = (4πr^3)/1029 × 3/(4πr^3)

V2/V1 = 3/1029

V2/V1 = 1/343

V2 = 1/343 x V1

Therefore, the volume of the sphere is multiplied by 1/343.

3 0
3 years ago
Is (3,2) a solution of the system of equations?Explain<br> 2x+y=8<br> -x+3y=4
lesya692 [45]

Answer:

no

Step-by-step explanation:

2(3)+2=8

6+2=8

-x+3y=4

-(3)+3(2)=4

-3+6=4

3 does not equal 4

7 0
3 years ago
An aerodynamic three-wheeled automobile (the Dart) runs on compressed natural gas stored in two cylinders in the rear of the veh
pogonyaev

Answer:

a) 7702.88 miles

b) If we drive more than 7702.88 miles per year, the dart would be more economical.

Step-by-step explanation:

Assuming a useful life of 7 years.

Let's calculate EUAC dart:

(15000)(A/P, 10%, 7) + (X/100mpg)(8)

= 15000 * 0.2054 + 0.08

= 3081.15 + 0.08X

EUAC For other automobile:

(12000)(A/P, 10%, 7) + (X/50mpg)(8)

= 12000 * 0.2054 + 0.16X

= 2464.92 + 0.16X

a) To solve for X, we have:

EUAC dart = EUAC other automobile

3081.15 + 0.08X = 2464.92 + 0.16X

0.08X - 0.16X = 2464.92 - 3081.15

-0.08X = - 616.23

X = 7702.88 miles

b) The range of annual miles driven is the Dart more economical.

EUAC dart < EUAC other automobile

3081.15 + 0.08X < 2464.92 + 0.16X

X > 7702.88 miles

If we drive more than 7702.88 miles per year, the dart would be more economical.

5 0
3 years ago
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.
qwelly [4]

Answer:

A)

\displaystyle \frac{dy}{dt}=-\frac{33}{8}

B)

\displaystyle \frac{dx}{dt}=\frac{3}{2}

Step-by-step explanation:

<em>x</em> and <em>y</em> are differentiable functions of <em>t, </em>and we are given the equation:

xy=6

First, let's differentiate both sides of the equation with respect to <em>t</em>. So:

\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6]

By the Product Rule and rewriting:

\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0

Therefore:

\displaystyle y\frac{dx}{dt}+x\frac{dy}{dt}=0

A)

We want to find dy/dt when <em>x</em> = 4 and dx/dt = 11.

Using our original equation, find <em>y</em> when <em>x</em> = 4:

\displaystyle (4)y=6\Rightarrow y=\frac{3}{2}

Therefore:

\displaystyle \frac{3}{2}\left(11\right)+(4)\frac{dy}{dt}=0

Solve for dy/dt:

\displaystyle \frac{dy}{dt}=-\frac{33}{8}

B)

We want to find dx/dt when <em>x</em> = 1 and dy/dt = -9.

Again, using our original equation, find <em>y</em> when <em>x</em> = 1:

(1)y=6\Rightarrow y=6

Therefore:

\displaystyle (6)\frac{dx}{dt}+(1)\left(-9)=0

Solve for dx/dt:

\displaystyle \frac{dx}{dt}=\frac{3}{2}

5 0
3 years ago
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