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3 years ago

Help. Really help. It’s timed. HELP PLEASE

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

7 0

Answer:

c i think

Step-by-step explanation:

set the denominator to equal 0

(x-7)(x+5) = 0

x = 7, x = -5

all real numbers except -5 and 7

hram777 [196]3 years ago

6 0

Answer:

its b

Step-by-step explanation:

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vekshin1

Answer:

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Step-by-step explanation:

Given;

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Answer:

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Step-by-step explanation:

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3 years ago

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Alika [10]

Answer:

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Step-by-step explanation:

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3 years ago

Find x, if 3x − 5(y + x ) ^2 = 16 and 4x + 2(y + x )^ 2 = 30

lana66690 [7]

Answer:

x = 7

Step-by-step explanation:

Start by solving for $(y+x)^2$ which is a common expression for both equations. Then in the first equation:

$3\,x5\,(y+x)^2=16\\3x-16=5\,(y+x)^2\\(y+x)^2=\frac{3\,x-16}{5}$

and in the second equation:

$4\,x+2\,(y+x)^2=30\\2\,(y+x)^2=30-4\,x\\(y+x)^2=15-2\,x$

Now we make the two $(y+x)^2$ expressions equal so we get:

$\frac{3\,x-16}{5} =15-2\,x\\3\,x-16=75-10\,x\\13\,x=75+16\\13\,x=91\\x=7$

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3 years ago