The answer is 29
let n be the first of the consecutive odd numbers
⇒ n, n+2, n+4 n+6, n+5
represent 5 consecutive odd numbers
sum = n+ (n+2) + (n+4) + (n+6) + (n+8) = 5n+20
⇒ 5n +20=145
Solve for n = 25
25, 27, 29, 31, 33
25+27+29+31+33=145
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Answer: To add integers having the same sign, keep the same sign and add the absolute value of each number. To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest. Subtract an integer by adding its opposite.
A)
Vf² = vi² + 2ad Subtract 2ad from both sides
Vf² - 2ad = vi² Find the square roots of both sides
√(Vf² - 2ad) = √(vi²) Cancel out the squares with the square roots
Vf - √(2ad) = vi Switch the sides to make it easier to read
vi = Vf - √(2ad)
B) Vf² = vi² + 2ad Subtract vi² from both sides
Vf² - vi² = 2ad Divide both sides by 2a
(Vf² - vi²) / 2a = d Switch the sdies to make it easier to read
d = (Vf² - vi²) / 2a
Well,properties can help you because you can shorten or make an equation more understandable, like using distributive property in the example 2(5x-3), you can rewrite it as 10x-6. See?
Answer:
D
Step-by-step explanation:
Count the number of places it takes to get one place past 3
There are 5 zeros in the given question. That gets you to just before the 3.
Add one more to get past the 3. That makes 5 zeros + 1 more place = 6
Since you are moving right, the 6 is minus. Your answer is 3 * 10^-6
