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Anon25 [30]
3 years ago
12

Omg I WILL MARK BRANLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THIS IS DUE TODAY

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

Please give more context to what you desire help for.

lesantik [10]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Its the first letter of the English alphabet

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Which is the equation of a line that has a slope of 3 and passes through point
Wewaii [24]

Answer:

y = -2/3x - 3

Step-by-step explanation:

y = -2/3x + b

-1 = -2/3(-3) + b

-1 = 2 + b

-3 = b

y = -2/3x - 3

6 0
3 years ago
What is equivalent to <br><img src="https://tex.z-dn.net/?f=13%20-%20%20%5Csqrt%7B%20-%2081%7D%20" id="TexFormula1" title="13 -
Radda [10]
√- 81 doesn't result in a rational number because you can't get a negative from squaring any number. Instead you get a number with an imaginary number. 

13 - √- 81 = 13 - 9i
7 0
3 years ago
If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
3 years ago
What is the equation of the line that passes through the points ( -2, -5) and (4,7)
kolbaska11 [484]

y=2x-1....

I think that's the answer

4 0
3 years ago
Many years ago, the towns of Franklin and Chester agreed to begin posting their populations on signs just outside of their towns
iVinArrow [24]

Answer:

The answer is 9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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