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2 years ago

I really need help with this. You can answer this at any time if you want.

Mathematics

1 answer:

Tcecarenko [31]2 years ago

8 0

Answer:

1. a 3d rectangle

2. 40 in cubed

3. repeat

4. another repeat

Step-by-step explanation:

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16. How many different words can be formed with the letters of the word 'RAJARAM'? In how many of

Mandarinka [93]

Answer:

The word "ARRANGE" can be arranged in

2!×2!

5040

=1260 ways.

For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.

Then the number of ways =

=360.

The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.

Also in the same way, the number of ways where two "A's" are together is 360.

The number of ways where two "A's" and two "R's" are together is 5!=120.

The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.

Step-by-step explanation:

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3 years ago

Read 2 more answers

cody spent two thirds of his weekly allowance on candy. to earn more money his parents let him wash wash the car for $5. what is

anastassius [24]

Explanation is in the file

tinyurl.com/wtjfavyw

3 0

2 years ago

What is the reciprocal of 3^-2 ?

weqwewe [10]

Answer:

1/3^2

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3 years ago

A Air Freshener Used 3 3/4 milliliters perfume wanted to make 3 air freshners how many milliliters of perfume woud she use

larisa [96]

1 and a fourth because 3 3/4 devided by three equals 1 1/4

5 0

3 years ago

How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.

Vaselesa [24]

Answer:

see below

Step-by-step explanation:

$-2(4 - \frac{x}{2} )^{5} + C$

Think of the above as:

$-\frac{2}{1}$ * $(\frac{8}{2} - \frac{x}{2} )^{5} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{2^{5}} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{32} + C$

= $-\frac{1}{1}$ * $\frac{(8 - x)^{5}}{16} + C$

= $\frac{-1(8 - x)^{5}}{16} + C$

= $\frac{(-8 + x)^{5}}{16} + C$

Can flip it around to be...

$\frac{(x - 8)^{5}}{16} + C$

4 0

3 years ago

I really need help with this. You can answer this at any time if you want.​

I really need help with this. You can answer this at any time if you want.