In algebra it is fully possible for x to equal to zero. After you have 2x, just divide both sides by two, so it would be 2 divided by 0 and than you would have x=0 and that would be your final answer.
2x + 1 = 4x +1
-2x +1 = 1
-2x = 0
divide by -2
x=0
I would think that all but one point would be on the line. One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation. Next time, would you please enclose the coordinates of each point inside parentheses: (2.5,14), (2.25,12), and so on, to avoid confusion.
14-12
slope of line thru 1st 2 points is m = ---------------- = 2/0.25 = 8
2.50-2.25
What is the eqn of the line: y = mx + b becomes
14 = (8)(2.5) + b; find b:
14-20 = b = -6. Then, y = 8x - 6.
Now determine whether (12,1.25) lies on this line.
Is 1.25 = 8(12) - 6? Is 1.25 = 90? No. So, unless I've made arithmetic mistakes, (1.25, 5) does not lie on the line thru (2.5,14) and (2.25,12).
Why not work this problem out yourself using my approach as a guide?
Probability =
(number of ways it can come out the way you want)
divided by
(total number of ways it can come out).
Total number of ways to draw a marble = 30 (marbles in the bag).
Number of ways it can succeed = 15 (number of red or green ones)
Probability = 15/30 = 1/2 = 50% .
I notice that The price is higher than the original price
And I wonder it is because of the tax?
F(x) =x² - 10x, f⁻¹(x) =?
1st find the missing square of x²-10x, ==> (x-5)² - 25
y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5
Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}
