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soldier1979 [14.2K]
3 years ago
6

Please help with this questions

Mathematics
1 answer:
sveta [45]3 years ago
7 0
La numero c es la correcta
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For a moving object,When. The force acting on the object varies directly with the object's acceleration. When a force of 64 N ac
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72 N

Step-by-step explanation:

From the question.

Force is directly proportional to acceleration, with the mass of the object constant.

F α a

F = ka

F₁/a₁ = F₂/a₂....................... Equation 1

Where F₁ = Initial force, a₁ = initial acceleration. F₂ = final force, a₂ = Final acceleration.

make F₂ the subject of the equation

F₂ = (F₁/a₁)a₂................ Equation 2

Given; F₁ = 64 N, a₁ = 8 m/s², a₂ = 9 m/s²

Substitute these values into equation 2

F₂ = (64/8)(9)

F₂ = 72 N

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4 years ago
NEED HELP NOW WITH MATH!!!! points 10
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D

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I tried the last one and it did not work so maybe D

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Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

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y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

8 0
3 years ago
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