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Verdich [7]
3 years ago
10

Find the midpoint of the line segment joining the points (9,2) and (-3,-2)

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

(3,0)

Step-by-step explanation:

The midpoint formula is as follows:

( (x1+x2) /2, (y1 + y2) /2 )

x1 would be 9, x2 would be -3, y1 would be 2, y2 would be -2. When plugged in, you should get 6/2, and 0/2 for y. When simplified, x would be 3 and y would be 0. This means that the midpoint of the line segment is (3,0)

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Juan's pit crew was able to get his car back onto the racetrack 0.4 seconds faster than Paul's crew. Paul's crew took 1.3 second
9966 [12]

Answer:

6.7 seconds

Step-by-step explanation:

Juan= Paul-0.4

Paul=Terry+1.3

We can substitute Terry+1.3 for Paul since they are equal

juan=(Terry-0.4)+1.3

terry=5.8

juan=(5.8-0.4)+1.3

juan=6.7

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3 years ago
I need help with this answer
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Answer:

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Step-by-step explanation:

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I will help you on two conditions:  1) that you never again call yourself "stupid," and that you ask no more than 1 or 2 questions per post.

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3 0
3 years ago
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1. Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise. What
Reil [10]

Answer: A'(3,2),  B'(0,1)  and C'(-4, -5).

Step-by-step explanation:

When we rotate (a,b) 90 degrees clockwise, the new point will be (b,-a).

i.e. rotation rule for 90 degrees clockwise : (x,y) → (y,-x)

Given: Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise.

Then, the new image points for triangle A'B'C' will be :

A(-2,3) → A'(3,-(-2)) =A'(3,2)

B(-1,0)→ B'(0,-(-1)) = B'(0,1)

C(5,-4) → C'(-4, -5)

Hence, the new image points for triangle A'B'C' are A'(3,2),  B'(0,1)  and C'(-4, -5).

6 0
3 years ago
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kykrilka [37]

Answer:

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Step-by-step explanation:

The sum of two sides of a triangle must be greater than the third side

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2 years ago
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