Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
Given:
The expression is

To find:
The equivalent expression.
Solution:
Distributive property of multiplication over addition is

Where, a, b and c are real numbers.
We have,

Using distributive property, we get


Therefore, the expression
is equivalent to the given expression.
I'm assuming this is a system of equations you want solved so,
x = -y + 3
-2(-y+3)+4y = 6
2y - 6 + 4y = 6
6y = 12
y = 2
x + 2 = 3
x = -1
(-1,2)
Answer:
<em>After </em><em>47</em><em> days she will have more than 90 trillion pennies.</em>
Step-by-step explanation:
At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.
The amount of pennies doubled each day. So the series is,

This series is in geometric progression.
As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

where,
a = initial term = 1,
r = common ratio = 2,
As we have find the number of days that would elapse before she has a total of more than 90 trillion, so








