A catering company is setting up for a wedding they expect 150 people to attend they can provide tables that seat 6 people and l
1 answer:
Answer:
(20,5) is NOT a solution of the equation .
The point (20,5) implies that there are 20 small tables and 5 large tables.
Step-by-step explanation:
We have been given that a catering company is expecting 150 people to attend the wedding. There are two types of tables, ones which can fit 6 people and ones which can fit 10 people.
If there are x tables which can fit 6 people and there are y tables which can fit 10 people, we can express the total number of people that can fit on all available tables as: .
Since there are total 150 people expected in the wedding, the equation can be framed as: .
Let us check if the point (20,5) is a solution of the equation.
Since we get a false statement, therefore, (20,5) is NOT a solution of the equation .
The point (20,5) implies that there are 20 small tables and 5 large tables.
You might be interested in
<h3>Answer:</h3>
Factor 6 from the first two terms.
<h3>Step-by-step explanation:</h3>By factoring out "a", you can better see what "h" needs to be.
- y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
- add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
- rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5