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Artemon [7]
3 years ago
6

Alaina was asked whether the following equation is an identity:

Mathematics
2 answers:
jarptica [38.1K]3 years ago
6 0

Answer: yerror she made is at the level of the first step if you want me to show it to you ask me in comment

                                   

3241004551 [841]3 years ago
3 0

Answer: made a step 1 mistake

Step-by-step explanation:

the step is incorrect because the expansion of (x+1)^2 is x^2+2x+1. But since there’s a minus sign before it , all plus signs should be changed to minus.

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Where are the x-intercepts for f(x) = −4cos(x − pi over 2) from x = 0 to x = 2π?
yKpoI14uk [10]
Recall that to get the x-intercepts, we set the f(x) = y = 0, thus

\bf \stackrel{f(x)}{0}=-4cos\left(x-\frac{\pi }{2}  \right)\implies 0=cos\left(x-\frac{\pi }{2}  \right)
\\\\\\
cos^{-1}(0)=cos^{-1}\left[ cos\left(x-\frac{\pi }{2}  \right) \right]\implies cos^{-1}(0)=x-\cfrac{\pi }{2}
\\\\\\
x-\cfrac{\pi }{2}=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}

\bf -------------------------------\\\\
x-\cfrac{\pi }{2}=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{2\pi }{2}\implies \boxed{x=\pi }\\\\
-------------------------------\\\\
x-\cfrac{\pi }{2}=\cfrac{3\pi }{2}\implies x=\cfrac{3\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{4\pi }{2}\implies \boxed{x=2\pi }
3 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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