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lara [203]
4 years ago
6

Three brothers have ages that are consecutive even integers the product of the first & third boys ages is 20 more than twice

the seconds boy age.find the age of each of the boys
Mathematics
1 answer:
Agata [3.3K]4 years ago
5 0
Let's say X is the first brother's age
x+2 is second brother, and x+4 is the third brother
Since the product of the first and third boy x(x+4) is 20 more than twice (20+x(x+2), our equation is x(x+4)=20+2(x+2)
Simplify from there and see what you get.
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What is the solution of −81=b6 ?<br> A. b = −486<br> B. b = −75<br> C. b = 13.5<br> D. b = 486
BartSMP [9]
We have to isolate b to be alone. 
Soooo first we divide both sides by 6

-81 = b6
÷6  = ÷6  The right side cancels out and gets the b alone. While we solve the right side of the equal sign. 
-81 ÷ 6 = -13.5 
So this means we isolated b alone!
b = -13.5 

Our final answer is..
b = -13.5 

:)

7 0
4 years ago
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Ahat [919]

Answer:

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Step-by-step explanation:

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3 years ago
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3 years ago
What does x equal 2(x-3)=14
Leno4ka [110]

Answer: x = 10

Explanation: To solve this equation for <em>x</em>, we start by distributing the 2 through the parentheses on the left side.

So we have 2 times <em>x</em> which is 2x and 2 times -3 which is -6. So our equation now reads 2x - 6 = 14.

Solving from here,

we add 6 to both sides of the equation and we have 2x = 20 and dividing both sides by 2, we find that <em>x = 10</em>.

We can check our answer by substituting a 10 back in for <em>x</em> in the original equation and we have 2(10 - 3) = 14.

10 - 3 is 7 so we have 2(7) = 14 or 14 = 14 which is a true statement so our answer checks.

3 0
4 years ago
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