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3 years ago

Find the inverse of y = In2x.

Mathematics

1 answer:

Amanda [17]3 years ago

7 0

Step-by-step explanation:

y=2x

interchanging the role of x andy

x=2y

y=x/2

:.inverse of y=2xis y=x/2

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Multiply (2x-5)(3x2-4x+2)

WITCHER [35]

Answer:The answer is 183, hope I helped.

8 0

3 years ago

let a,b,c,d be four integers (not necessarily distinct) in the set {1,2,3,4,5}. the no. of polynomials x^4+ax^3+bx^2+cx+d which

Eddi Din [679]

By either long or synthetic division, it's easy to show that

$\dfrac{x^4+ax^3+bx^2+cx+d}{x+1}=x^3+(a-1)x^2+(-a+b+1)x+(a-b+c-1)-\dfrac{a-b+c-d-1}{x+1}$

The quartic will be exactly divisible by $x+1$ when the numerator of the remainder term vanishes, or for those values of $a,b,c,d$ such that

$a-b+c-d-1=0$

I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.

8 0

3 years ago

If you can explain your answer that’d be great!! Thank you!

Rasek [7]

Answer:

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

$A(t)=A_{0}e^{kt}$

Where

$k=\frac{ln(\frac{1}{2})}{Half-Life}$

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

$k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}$

Now

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

third choice is correct.

8 0

3 years ago

Help asap pleaseeeee

Elena-2011 [213]

The answer is "above" because the inequality says 2x - 2 > 2 meaning the values must be are greater than that of y = 2.
Its not "intersects" because it would be the equation 2x - 2 = 2

6 0

3 years ago

Solve.

Anton [14]

They were born 2336 years apart.

384+1952=2336

7 0

3 years ago