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3 years ago

If the first term is 3 (A1=3) and the common difference is 4 (d=4) what is the fifth term? (A5=?)

Mathematics

1 answer:

omeli [17]3 years ago

3 0

Answer:

Pov:شما به ترجمه گوگل رفت برای دیدن آنچه من گفتم و دیدم این xD

Step-by-step explanation:

Pov:شما به ترجمه گوگل رفت برای دیدن آنچه من گفتم و دیدم این xD

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Three of the angles of a quadrilateral are 120 48 and 92 what is the size of the 4th angle

IgorLugansk [536]

You do 120+48+92=280 All angles in a quadrilateral add up to 360, so 360-280=80 The answer is 80 HAVE FUN DOING MATHS!

6 0

3 years ago

Read 2 more answers

An exponential random variable has a standard deviation of 16. Calculate The probability that it takes on a value < 11. Use 3

antiseptic1488 [7]

Answer:

$P(X$

And using the cdf we got:

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable that represent the random variable of interest and we know that the distribution is given by:

$X \sim Exp(\lambda)$

We know the variance on this case given by :

$Var(X) = \frac{1}{\lambda^2}$

So then the deviation is given by:

$Sd(X) = \frac{1}{\sqrt{\lambda}}$

And if we solve for $\lambda$ we got:

$\lambda = (\frac{1}{16})^2 = \frac{1}{256}$

The cumulative distribution function for the exponential distribution is given by:

$F(x) = 1- e^{-\lambda x}$

Solution to the problem

And for this case we want to find this probability:

$P(X$

And using the cdf we got:

$P(X$

5 0

3 years ago

Tomas Scheckter won the Bombardier Learjet at Texas Motor Speedway by edging the

GenaCL600 [577]

Answer:

5.34 x 10^-2

Step-by-step explanation:

8 0

3 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Expand the number 1120 into its corresponding exponential form. 25 · 5 · 7 52 · 8 22 · 53 · 7 2 · 5 · 7

Eduardwww [97]

Answer:

(A) 2^{5} * 5 * 7

Step-by-step explanation:

Your question formatting made it very complicated to understand the possible answers. Please use some notation or the equation editor next time.

So, the exponential form a way to write a number using multiplications and powers.

Let's examine the various options (if I read them correctly)

(A) 2^{5} * 5 * 7 - YES!

2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120

(B) 5² · 8 - NO

= 25 * 8 = 200

(C) 2² * 5³ * 7 - NO

= 4 * 125 * 7 =500 * 7 = 3500

(D) 2 · 5 · 7 - NO

= 10 * 7 = 70

5 0

3 years ago

If the first term is 3 (A1=3) and the common difference is 4 (d=4) what is the fifth term? (A5=?)​

If the first term is 3 (A1=3) and the common difference is 4 (d=4) what is the fifth term? (A5=?)