Write the equation of the line that passes through the points (3, 4) and (5, 8)

Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati

Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c. D. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X $\sim$ N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

$P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})$

$P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})$

$P(X < 76) = P(Z< \dfrac{3}{12.5})$

$P(X < 76) = P(Z< 0.24)$

From the standard normal distribution tables,

$P(X < 76) = 0.5948$

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

$P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})$

$P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})$

$P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})$

$P( \overline X < 76) = P(Z< 1.2)$

From the standard normal distribution tables,

$P(\overline X < 76) = 0.8849$

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

In order to determine the probability in part (b); the normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0

3 years ago

The math department sold pie slices to buy new math books. Two pies were contributed by members of the department. Each pie was

kenny6666 [7]

The answer is 8, just divide 6 by 48. Hope it helped.

8 0

3 years ago

Read 2 more answers

You are applying for an 80/20 mortgage to buy a house costing $145,000. The first (80%) mortgage has an interest rate of 4.75%,

babymother [125]

Answer:

$291,016.80

A is correct.

Step-by-step explanation:

You are applying for an 80/20 mortgage to buy a house costing $145,000.

Loan Formula:

$EMI=\dfrac{P\cdot r}{1-(1+r)^{-n}}$

Case 1:

Loan amount, P = 80% of 145000 = $ 116,000

Rate of interest, r = 4.75% = 0.0475

Time of loan, n = 30 years = 360 months

Substitute the values into formula.

$EMI=\dfrac{116000\cdot \frac{0.0475}{12}}{1-(1+\frac{0.0475}{12})^{-360}}$

$EMI=605.11$

Total payment for case 1: 605.11 x 360 = $217,839.60

Case 2:

Loan amount, P = 20% of 145000 = $ 29,000

Rate of interest, r = 4.75% = 0.07525

Time of loan, n = 30 years = 360 months

Substitute the values into formula.

$EMI=\dfrac{29000\cdot \frac{0.07525}{12}}{1-(1+\frac{0.07525}{12})^{-360}}$

$EMI=203.27$

Total payment for case 1: 203.27 x 360 = $73,177.20

Total amount of the mortgage = $217,839.60 + $73,177.20

= $291,016.80

Hence, The total amount of the mortgage is $291,016.80

3 0

3 years ago

Can someone please explain?

GREYUIT [131]

The function y = x, called the "identity" or "ramp" function, is a basic function that you'll need to add to your math vocabulary. Since the " x " here seems to have no exponent, fix that by thinking "x^1," or "x to the first power," or "y=x is a linear function."

The graph of y=x always goes thru the origin. It begins in the 3rd quadrant and ends in the 1st, and appears as a straight line with slope of m = rise / run = 1/1 = 1.

8 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.