M = 135/19 and n = -5/19
You have to give them like terms so that when you eliminate they cancel out and you can solve. The easiest way to do so is by multiplying the top equation by -4 and the bottom by 3.
Item | Frequency
0 | 2
1 | 5
2 | 4
3 | 3
5 | 1
Hope I helped!
Focus of a parabola:
where vertex (h,k) p is the distance from vertex to focus
Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
