Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
Answer:
Step-by-step explanation:
The answer is fifteen
Explanation: 6-3/0.4-0.2=3 over 0.2 which is equivalent to 15
The value of the number is 200
An obtuse angle is an angle with more than 90 degrees and less than 180. so, we can add < 180 and > 90 to the expression, making it the inequality 180 < 3x + 24 > 90. we then solve.
3x + 24 > 90 and 3x + 24 < 180
3x > 66 and 3x < 156
x > 22 and x < 52
so x can be anything more than 22 and less than 52 (it cannot be 52 or more or 22 or less)
hope this helps!
