The <u>correct word form of 8.16</u> is b. eight and sixteen hundredths
Since the number is 8.16, we have 8.16 = 8 + 0.16 = 8 + 16/100
Since we have 8 in the units place, it is pronounced eight.
Also, we have our decimal part 0.16 = 16/100 which is pronounced as sixteen hundredths.
So, combining both we have eight and sixteen hundredths.
So, the <u>correct word form of 8.16</u> is b. eight and sixteen hundredths
Learn more about decimals here:
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Answer:
RV = 15, ∠ VUR = 48°
Step-by-step explanation:
The diagonals of a rectangle are congruent , so
RT = SU , that is
5x - 10 = 4x - 2 ( subtract 4x from both sides )
x - 10 = - 2 ( add 10 to both sides )
x = 8
Then
RT = 5x - 10 = 5(8) - 10 = 40 - 10 = 30
The diagonals bisect each other , then
RV = 0.5 × 30 = 15
---------------------------------------------------------------
∠ RVU = ∠ svt = 84° ( vertical angles )
RV = UV ( diagonals are congruent and bisect each other )
Then Δ RVU is isosceles with base angles congruent , then
∠ VUR =
=
= 48°
Isolate the k. Note the equal sign. What you do to one side, you do to the other.
First, subtract 2m from both sides
8k + 2m (-2m) = 3m (-2m) + 4
8k = m + 4
Next, divide 8 from both sides
(8k)/8 = (m + 4)/8
k = (m + 4)/8
k = m/8 + 1/2
k = m/8 + 1/2 is your answer
hope this helps
Answer:
a
OR 
b
and
OR
and 
c
Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period
d

Step-by-step explanation:
From the question we are told that
The population model is 
Generally at equilibrium

So

=>
Or

=> 
Thus at equilibrium P = 0 or P = 135
Generally when the population is increasing we have that

So

=> 
and
Now when the first value of P i.e
for
So when population increasing the values of P are
and
OR
and 
So to obtain initial values of P where the population converge to the carrying capacity as ![t \to [\infty]](https://tex.z-dn.net/?f=t%20%5Cto%20%5B%5Cinfty%5D)
The rate equation can be represented as

So we will differentiate the equation again we have that

Now as

So
=> 
=> 