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marta [7]
3 years ago
12

Please help me please

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

2x+8x+6

Step-by-step explanation:

       

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Consider H0: μ = 45 versus H1: μ < 45. A random sample of 25 observations produced a sample mean of 41.8. Using α = .025 and
a_sh-v [17]
Given
H0: \ \mu=45 \\  \\ H1: \ \mu\ \textless \ 45
This is a one-tailed test.

z= \frac{41.8-45}{6/ \sqrt{25} } = \frac{-3.2}{6/5} = \frac{-3.2}{1.2} =-2.6667

P(z\ \textless \ -2.6667)=0.00383

Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.
5 0
3 years ago
How do i write 5,972,000,000,000,000,000,000,000kg in Scientific Notation
never [62]
In order to write this in scientific notation, we must move the decimal from the beginning all the way to between the 5 and the 9
Note: you can move the decimal anywhere you want but typically scientific notation will have the decimal in between the first and second digit.

Since we move the decimal 24 digits to the right, our answer will be

5.972 * 10^24
or
5.972E24

Hope this helps!!
8 0
3 years ago
Read 2 more answers
Consider a triangle with two sides that
AURORKA [14]

9514 1404 393

Answer:

  C)  14 cm

Step-by-step explanation:

A triangle solver can quickly show you the third side is 14 cm.

__

The law of cosines can be used for this purpose. If the given sides are 'a' and 'b', and the third side is 'c', then that law tells you ...

  c² = a² +b² -2ab·cos(C)

  c² = 7² +11² -2·7·11·cos(100°) ≈ 196.74

  c ≈ √196.74 ≈ 14.03

The length of the third side is about 14 cm.

8 0
3 years ago
HELPPP<br> From 8 A.M. to noon, the temperature change was -16F. Find the average change per hour
dimaraw [331]
-16F temperature change divided by 4 hour difference from 8 to 12/noon.
-16 divided by 4 = -4
The answer is -4 degrees Fahrenheit.
3 0
3 years ago
Please help will give brainly points
Mkey [24]

Answer:

-11

Step-by-step explanation:

if you put the numbers of the variebles in, it would be

-6-9+9-5

4 0
3 years ago
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