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3 years ago

Rd

Mathematics

1 answer:

taurus [48]3 years ago

4 0

Answer:

can you please write it differently cuz its kinda confusing

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(Area of Composite Figures)Help me pls.

oksian1 [2.3K]

Answer:

69 centimeters squared

Step-by-step explanation:

First, find the area of the big square = 11cm * 4cm = 44cm

Next, find the area of the leftover square = 5cm * 5cm =25cm

Add them together to get 69 centimeters squared

Hopefully this helps - let me know if you have any questions!

6 0

2 years ago

Read 2 more answers

Which table represents a linear function?<br> PLEASE HELP ME

-Dominant- [34]

Answer:

Bottom left

Step-by-step explanation:

If you graph out the coordinates it goes in a perfect line, thus being linear.

6 0

2 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Which of the following is the graph of the absolute-value parent function?

Ne4ueva [31]

Should have the ordered pairs of
(-4,4) (-3,3) (-2,2) (-1,1) (0,0) (1,1) (2,2) (3,3).

Will look like a V when graphed. Reason being is if you take the absolute value of anything you are basically just dropping the negative sign as it is how far away it is from 0.

4 0

3 years ago

1.) If I am selling a dozen at $3, how much would each egg cost?

riadik2000 [5.3K]

Answer:

1.$3÷12=0.25

each egg would cost 25 cents

2.12×18=216

216×25=5,400

6 0

3 years ago