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rosijanka [135]

3 years ago

10

A teacher needs to choose seven students to hand out papers. The total number of ways he may choose the students can be found us

ing a combination

2 answers:

Vlad [161]3 years ago

8 0

Answer:

True

Step-by-step explanation:

Apex

sladkih [1.3K]3 years ago

7 0

It may be 2 students

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The height h in feet of a ball thrown vertically upward from the top of a 288-foot tall building is given by h=288+48t-16t^2 whe

mr Goodwill [35]

6 sec can take penny to strike the ground.

Solution:

Given data:

$H_0=288$ feet

$V_0=48$ feet

$h(t)=288+48t-16t^2$

Re-arrange the terms from greatest degree to smallest degree.

$h(t)=-16t^2+48t+288$

We can solve it by applying quadratic formula,

$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a = –16, b = 48, c = 288

$$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}$

$$t=\frac{-48\pm \sqrt{2304+18432}}{-32}$

$$t=\frac{-48\pm \sqrt{20736}}{-32}$

$$t=\frac{-48\pm144}{-32}$

Now, write find two t's using plus and minus operation.

$$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}$

$$t=\frac{96}{-32},\ \ t=\frac{-192}{-32}$

t = –3 (or) t = 6

We cannot write time is negative. so neglect t = –3.

Therefore t = 6.

Hence 6 sec can take penny to strike the ground.

8 0

2 years ago

A youth group is setting up camp. Rain is predicted, so the campers decide to build a fly, or rain cover, over their tent. The f

pshichka [43]

The image for this is attached for reference. This problem can be used by the Pythagorean equation. To make solving convenient, let us see only one part of the tent. Hence, one side is half of the tend width which is 16/2ft. Height is 12 ft. The unknown side is the hypotenuse. The answer is:
$a^{2} + b^{2} = c^{2} 8^{2} + 12^{2} = c^{2} c = 14.4$

7 0

3 years ago

Which graph is defined by the function given below? Y=(x-1)(x+4)

Andrej [43]

Answer:Graph C

Step-by-step explanation:

4 0

3 years ago

Solve for x. Picture attached <br><br> Show your work please!!!

Iteru [2.4K]

The answer is going to be x=22

8 0

2 years ago

Read 2 more answers

In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. if there were 45 basket

IgorLugansk [536]

Let
x: number of regular basketball
y: number of long-distance basket
We have the following system of equations:
2x + 3y = 96
x + y = 45
Solving the system we have
y = 45-x
2x + 3 (45-x) = 96
2x +135 -3x = 96
-x = 96 -135
x = 39
Then,
y = 45-x
y = 45-39
y = 6
answer
were made
regular baskets = 39
long-distance baskets = 6

3 0

3 years ago