Answer:
First option: cos(θ + φ) = -117/125
Step-by-step explanation:
Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.
Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.
Therefore:
cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)
cos(θ + φ) = (-96/125) - (21/125)
cos(θ + φ) = -96/125 - 21/125
cos(θ + φ) = -117/125
meme break
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ANSWER
The correct answer is C
.
<u>EXPLANATION</u>
We have

and
.
We solve the two equation simultaneously by elimination method. We need to be smart and eliminate y, since we are looking for
.
We first multiply equation (2) by 2
.
We add equation (3) and (1).
.
Dividing through by 6 gives
.
Step-by-step explanation:
To write the equation in LaTeX in form y = ab^x or
for y = abx .........(1)
(a) LaTeX: y=3\sqrt{4^{2x}} y = 3 4 2 x can be written in mathematical form as
; y = 342x
on comparing with equation (1) we get a =3 and b =4
⇒y = 34^x or 
(b) LaTeX: y=\frac{\sqrt[3]{5^{3x}}}{2} y = 5 3 x 3 2 can be written in mathematical form as
; y = 342x
on comparing with equation (1) we get a =0.5 and b =5
⇒y =
(c)LaTeX: y=8^{x+2} y = 8 x + 2 can be written in mathematical form as
on comparing with equation (1) we get a =64 and b =8
y = 
(d)LaTeX: y=\frac{3^{2x+1}}{\sqrt{3^{2x}}} can be written in mathematical form as
=
= 
on comparing with equation (1) we get a =3 and b =3
y =
Answer:
Neither
Step-by-step explanation: