3 years ago

Which transformation is a dilation?

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

B. represents a dialation

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All sides of a square and a pentagon are 9 inches long. Are their perimeters the same? Explain

EastWind [94]

No they wouldn't be the same because, the perimeter is adding all sides.

The square has 4 sides so you would add 9, four times.

9 + 9 + 9 + 9 = 36

And a pentagon has 5 sides so you would add 9, five times.

9 + 9 + 9 + 9 + 9 = 45

So, they are not the same.

Hope this helps. :)

4 0

4 years ago

A rectangle has an area of 616 m² and a width of 22m. What is its length?

daser333 [38]

Answer:

l=28m

w Width

A Area

616

m²

Using the formula

A=wl

Solving forl

l=A

w=616

22=28m

hope this will help you

make me brainliest

8 0

3 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$