What is the probability of rolling two dices whose sum is prime

1 answer:

7 0

The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12.

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Can someone help me with this pls?

madam [21]

Please bare with me bc I’m bad at wording things, change it as you please!

It’s a minimum. I know that the function is a minimum because whenever there is a - in the beginning of the equation it flips your parabola over the x axis and my parabola becomes concave down. When my parabola is concave up I have a minimum, vise versa is a maximum. Because there isn’t a -, my parabola is concave up meaning the function has a minimum

6 0

2 years ago

The switchboard in a Minneapolis law office gets an average of 5.5 incoming phone calls during the noon hour on Mondays. Experie

trasher [3.6K]

Answer:

2.35 calls

Step-by-step explanation:

The presented scenario can be modeled by a Poisson distribution with an average number of calls (μ) of 5.5 during the noon hour on Mondays.

Therefore, the standard deviation for the number of calls received, X, is given by:

$\sigma =\sqrt \mu\\\sigma =\sqrt5.5\\\sigma =2.35\ calls$

The standard deviation of X is 2.35 calls.

3 0

3 years ago

Read 2 more answers

If sec(theta) =25/24, find cot(theta) (Picture provided)

larisa [96]

Answer:

Step-by-step explanation:

By the definition,

$\sec \theta=\dfrac{\text{hypotenuse}}{\text{adjacent leg}}.$

If $\sec \theta=\dfrac{25}{24},$ we can consider right triangle with hypotenuse 25 un. and adjacent leg 24 un. By the Pythagorean theorem,

$\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{opposite leg}^2=25^2-24^2,\\ \\\text{opposite leg}^2=625-576,\\ \\\text{opposite leg}^2=49,\\ \\\text{opposite leg}=7\ un.$