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3 years ago

Can somebody plz help answer both questions correct (only if u know how)

Mathematics

1 answer:

zhenek [66]3 years ago

8 0

divide the fraction like 4/5 and I'll give you decimal form and you could tell which one was bigger very quickly

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Use the divergence theorem to calculate the surface integral z s ~f d~s ; that is, calculate the ux of ~f across s, where ~f = z

MAXImum [283]

By the divergence theorem,

$\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV$

where $R$ is the solid whose boundary is $S$ . We have

$\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial zx}{\partial z}=1+x$

so we set up the volume integral as

$\displaystyle\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV=\int_{x=0}^{x=1/a}\int_{y=0}^{y=(1-ax)/b}\int_{z=0}^{z=(1-ax-by)/c}(1+x)\,\mathrm dz\,\mathrm dy\,\mathrm dx$
$=\dfrac{4a+1}{24a^2bc}$

7 0

4 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

3 years ago

HELP ASAP!!!!!!!!!!!!!!!

denpristay [2]

Answer:

I dont know :(

Step-by-step explanation:

4 0

3 years ago

Award brainly for random response! Ü

GenaCL600 [577]

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3 years ago

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Novosadov [1.4K]

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3 years ago

Read 2 more answers