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Pani-rosa [81]
3 years ago
12

I need help with this question.

Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0
Hello
how are u?

hope well  so the answer to this is going to be 

0 and 2
lbvjy [14]3 years ago
4 0
0 and 2 are your answers, since the numbers in the table match
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The school ski club went on a ski trip. The ski changed the group $1120 for 32 lift tickets. How much was each ticket?​
katen-ka-za [31]

Answer:

$35 per ticket

Step-by-step explanation:

1120 divided by 32 is 35, I used a calculator. If you divide the cost by the quantity you will get the cost for one quantity

3 0
3 years ago
PLEASE HELP ASAP
Zielflug [23.3K]
No cause it will cost here half that much to do the hole thing
4 0
3 years ago
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Help? i really don’t understand :(((
horsena [70]

Answer:

whats the question

Step-by-step explanation:

6 0
3 years ago
I am really stuck for how to solve x with algebra it is so confusing does anyone have any tips
MAXImum [283]
<span>Example: x − 2 = 4</span>

When we put 6 in place of x we get:

6 − 2 = 4

which is true

So x = 6 is a solution.

8 0
3 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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