Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
Read more on Brainly.com - brainly.com/question/8858421#readmore
Answer:
B its 4 7/8 --------------
Answer:
- Doug's garden: 87 lbs
- Kelsey's garden: 15 lbs
Step-by-step explanation:
Let k represent the pounds of produce coming from Kelsey's garden. Then Doug's garden produces 5.8k pounds of produce, and the total weight of it is ...
k + 5.8k = 102
6.8k = 102 . . . . . . . . . . . simplify
k = 102/6.8 = 15 . . . . . . pounds of produce from Kelsey's garden
5.8k = 5.8·15 = 87 . . . . pounds of produce from Doug's garden