Marcus needs to rewrite f(x) = x2 + 6x + 4 in vertex form. His answer is f(x) = ()2 – 5.
2 answers:
Answer:

Step-by-step explanation:
Given is a quadratic equation as

To complete the square we have to suitably add and subtract a term depending on the coefficient of x.
Here coefficient of x =6 and coefficient of x square =1
Hence we have to add (6/2)^2=9 to make it a perfect square

Now we completed the square and made it in vertex form
Vertex is (-3,-5)
and

Find the vertex. which is (-3,-5) the plug it into the equation y=a(x-h)^2+k
the equation would be Y= (x+3)^2-5 :)
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